AineHH9 3 ocTaqe10

He 3aB>KAL4 OAHe HaTypaJ1bHe qmcno MO>KHa nogiJIL,1Tm Ha iHl.ue Hagino.

                                           Hanpv•1KnaA,                                                  ABOM               Tpe6a noAiJ1b4Tb4 Mix c06010 7

14YKePOK, TO KO)KeH OAeP)KVlTb no 3 14YKePKV1 i 1 14YKepKa ganVIWVlTbCR B ocTaqi.

in        in        in             iii   i*iiiii

-iiiiiiiiiiii KOPOTKO 3anmcYl-0Tb: 7:2=3 (OCT 1). TYT qmcno 7 - AineHe, 2 AiJ1bHVlK, 3 - HenoBHa qaCTKa, 1 - ocTaqa.

TaK, OCKiJ1bKVl KOJI" OCTaqa 6iJ1bl.ua 3a AinbHVlK, TO AineHH9 MO)KHa nPOAOB)KYBaTVl gani. Lle A06pe BVIAHO Ha nphKnagi AineHH9 qmcen KYTOM.

_45 671L1--

                                                                                                           14 S                             uenooua qacmxa

iiiiiiiiiiiiiii

-5 7

5 5

2 ocmaua

                in   iii iiiiiiii iii iiiiiiii iii iiiiiii

Hanpvll<naa, 15:5=3

3aaaqi Ha AineHH51 3 ocTaqe10iiiiiiii

IIPVI AineHHi Hagino AineHe MO)KHa BVlpa3VlTVl yepea AiJ1bHVlK i yacTKY.

HanpvlKnaA, "KLUO 15:5=3, TO 15=5*3. MipKY10HL4 aHanoriHH0, MO>KHa

CKnaCTVl  .3Haxog:VKeHHfi AineHoro i npm AineHHi 3 OCTaye10.

Hanpb4KnaA, "KLUO 15:6=2(OCT. 3), TO 15=6*2+3.

•••••iii iii iiiiiii

fiKl.uo npvl AineHHi qmcna a Ha HI/ICJIO b oaeP>KYFOTb

HenoBHY qacTKY q i ocTaqy r, T06TO

       b.   iii iiiiiiii iii iiiiiii

149 cpopxnyna A03BOnne 3HaXOAVlTVl AineHe, 91<140 BiAOMi AiJ1bHVIK, HenoBHa qacTKa i ocTaqa.

«шлення з остаче»»

а

д[пене неповна остача частка де а:ђ = О !r<b

                         -13

59

52

(ост. 7)

189=1344+7

                     •i iii iiiiiiii ii“iiiiiii iii iiiiiii

Щоб одержати   час  з остачею, треба   помножити на неповну частку i додати остачу.

3aBAaHH9 B niAPYHHVlKY

¯iiiiiiiiiii flVlCbMOBO: NQ441

in     in     in iii iiiiiiii iii iiiiiiii iii iiiiiii