Рівняння виду sin x = b.

sin x = 1

sin x = 0

sin x = 0,5

sin x = 2

x = (-1)ⁿπ∕6 + πn, n∈Z

x = (-1)ⁿπ∕3 + πn, n∈Z

x = (-1)ⁿπ∕4 + πn, n∈Z

Розв'язків немає

 x = (-1)ⁿ⁺¹π∕6 + πn, n∈Z

x = (-1)ⁿ⁺¹π∕3 + πn, n∈Z

x = (-1)ⁿ5π∕6 + πn, n∈Z

x = (-1)ⁿ⁺¹π∕4 + πn, n∈Z

(-1)^k+1⋅ π/8+πk/2,k∊Z

(-1)^k ⋅ π/4+2πk

(-1)^k ⋅ π/8+πk,k∊Z

Розв'язків немає

x=πn/5; n∈Z

x=π/5 + 2πn/5; n∈Z

x=-π/5 + 2πn/5; n∈Z

x=π/10 + 2πn/5; n∈Z

 x=-π/10 + 2πn/5; n∈Z

π/18+πn/3, n∈Z

(-1)ⁿ⋅π/18+πn/6, n∈Z

(-1)ⁿ⋅π/36+πn/6, n∈Z

π/36+πn/3, n∈Z

x = -π + 4πn, n∈Z

x = -4π + 4πn, n∈Z

x = ±π∕2 + 2πn, n∈Z

x = 3π∕4 + 2πn, n∈Z

x = (-1)ⁿ⋅π∕18 + π∕3(n - 1), n∈Z

x = (-1)ⁿ⋅π∕9 + π∕3(n - 1), n∈Z

x = (-1)ⁿ⁺¹⋅π∕18 + π∕3(n - 1), n∈Z

x = -π∕3 + πn∕3, n∈Z